In addition to the Problem of the Week that goes up in the classroom, I will occasionally propose a problem here with the same basic rules (less people hand it in = more marks). Each will be given a specific due date (not necessarily always a week). Check back often to see Homework and BlogPOTW's.
Here's your first one:
There is an island at the equator, and on the island is a fleet of jets. The island also has the only fuel source for the jets. With a full tank, each jet can fly halfway around the world (at the equator). Since there is nowhere else to get fuel, they would crash...but...any other jet can help refuel them in mid-air (with a portion of their own fuel)...but must keep enough for them to safely return to the island.
The question then is this: What is the fewest number of jets (and more importantly, how can it be done), so that one single jet is able to fly around the entire world (without landing obviously).
This puzzle is due next Thurs (before March break), and is worth double the points (as our first BlogPOTW)...with the points being divided 5, 3, and 2..to the top 3 answers in each class.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment